Question

WILL FANN & MEDALL

How many real-number solutions does the equation have?

-7x^2 + 6x + 3 = 0

a. one solution
b. two solutions
c. no solutions
d. infinitely many solutions

Answer 1

@Here_to_Help15

Answer 2

Let first check the discriminant value of this equation shall we:
\[ax^2 + bx + c = 0\]
Discriminant formula says that:
\[\Delta = b^2 + 4ac\]

if \[\Delta = 0\] there wil be one real-value solution.
if \[\Delta < 0\] there will be no real-value solution
if \[\Delta > 0\] There will be two real value solution.

In here
\[\Delta = 6^2 - 4 \times (-7)(3) = 120 > 0\]

So as we stated earlier discriminant is greater than 0. So two real values solution exist.

Answer 3

thxxx!!! :)