Question

how do i simplify sqrt of P^7

Answer 1

sqrt of n/25?

Answer 2

and sqrt of y^2 / 7

Answer 3

which part?

Answer 4

\[(P ^{7})^{1/2}\]

Answer 5

i dont know how to work that out...sorry...

Answer 6

So we can multiply it out, to reach \[P ^{7/2}\]

Answer 7

yes, that makes sense. its coming back to me now :)

Answer 8

Okay =)

Answer 9

shoot. so then would that be the answer or do we have to work it out even more?

Answer 10

P^(7/2) looks simplified enough to me.

Answer 11

ok wow thanks! what i wanna know is how you got the p7 (1/2 )

Answer 12

how many times does 2 go in to 7?

Answer 13

because \[\huge p^{\frac{7}{2}}\] is not the answer you are looking for

Answer 14

ok makes sense now :) thank you

Answer 15

let me repeat my self
that is NOT the answer

Answer 16

yes i know haha

Answer 17

\[\sqrt{p^7}=\sqrt{p^6\times p}=\sqrt{p^6}\sqrt{p}=p^3\sqrt{p}\] is the final answer

Answer 18

more simply realized as "2 goes in to 7 3 times with a remainder of 1, so \(p^3\) comes outside the radial, \(p\) stays in

Answer 19

oh okay thanks for verifying

Answer 20

yw

Answer 21

so what if i had sqrt of n/25?

Answer 22

@satellite73

Answer 23

\[\huge \sqrt{\frac{n}{25}}\] like that?q

Answer 24

yes :) @satellite73

Answer 25

then since \(\sqrt{25}=5\) you have
\[\frac{\sqrt{n}}{5}\]

Answer 26

thats it? :p

Answer 27

yup

Answer 28

cool. last question is sqrt of y^2/7

Answer 29

\[\huge \sqrt{y^{\frac{2}{7}}}\]?

Answer 30

yes its y^2 on the top nad 7 on the bottom

Answer 31

*and

Answer 32

@satellite73

Answer 33

oh i see

Answer 34

\[\sqrt{y^2}=y\]so first step is
\[\frac{y}{\sqrt{7}}\]

Answer 35

then if you have to rationalize the denominator
\[\frac{y}{\sqrt{7}}\times \frac{\sqrt7}{\sqrt7}=\frac{y\sqrt7}{7}\]

Answer 36

ok cool. thats always the confusing part... so would that be the answer? \[y \sqrt{7}/7 \]

Answer 37

yes

Answer 38

thanks !

Answer 39

yw hope it helped

Answer 40

it did your very helpful :)