Question

HELP PLEASE
Given the following triangle, find c.

Answer 1

\[c=\sqrt{15^2+9^2}\] by pythagoras

Answer 2

306? @satellite73

Answer 3

oh no

Answer 4

http://www.wolframalpha.com/input/?i=sqrt%2815^2%2B9^2%29

Answer 5

originally i had put 18 sq root (17) @ satellite73

Answer 6

think you forgot to take the square root maybe

Answer 7

\[3\sqrt{34}\]if you want the exact answer

Answer 8

oh okay thanks. Can you help me with one more please? @satellite73

Answer 9

kk

Answer 10

Evaluate tan60 divided by cos 45

Answer 11

\[\frac{\tan(60)}{\cos(45)}\]?

Answer 12

i got it in a decimal form but it has to be one of these

Answer 13

yeah @satellite73

Answer 14

\[\tan(60)=\sqrt3\\
\cos(45)=\frac{\sqrt2}{2}\]

Answer 15

divide by multiplying by the reciprocal as usual
\[\sqrt3\times \frac{2}{\sqrt2}\]

Answer 16

so would the answer be 1 over sq root 6 @satellite73

Answer 17

you get
\[\frac{2\sqrt 3}{\sqrt2}\]

Answer 18

multiply top and bottom by \(\sqrt2\)
\[\frac{2\sqrt3}{\sqrt2}\times \frac{\sqrt2}{\sqrt2}\]\[=\frac{2\sqrt6}{2}=\sqrt6\]

Answer 19

OH. okay that makes sense thank you so much!! @satellite73

Answer 20

no not \(\frac{1}{\sqrt6}\) just \(\sqrt6\)

Answer 21

yw