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Mathematics 21 Online
OpenStudy (anonymous):

Evaluate the expression. r = <5, 9, -4>, v = <3, 3, -8>, w = <9, -6, -1> v ⋅ w

OpenStudy (asnaseer):

what have you tried? where are you stuck?

OpenStudy (anonymous):

When I try to subrtact them I just don't get the right answer

OpenStudy (asnaseer):

this is a dot product of two vectors. Do you know how to calculate the dot product?

OpenStudy (anonymous):

no

OpenStudy (asnaseer):

if you have two vectors: \(a=<a_x,a_y,a_z>\) and \(b=<b_x,b_y,b_z>\), then their dot product is defined as:\[a.b=a_xb_x+a_yb_y+a_zb_z\]

OpenStudy (anonymous):

So then I'm just trying to multiply each of them together?

OpenStudy (asnaseer):

multiply each component of the vectors and add the result - yes. you may find this site helpful to learn more about this: https://www.mathsisfun.com/algebra/vectors-dot-product.html

OpenStudy (anonymous):

Ok thank you, I thought that I was trying to subtract the two..

OpenStudy (asnaseer):

yw :)

OpenStudy (anonymous):

I have another question..

OpenStudy (asnaseer):

<--- please post each question separately on the left

OpenStudy (anonymous):

It is about this

OpenStudy (asnaseer):

oh - sorry - then go ahead please

OpenStudy (anonymous):

No problem.. what happens when you have a variable in the dot product?

OpenStudy (anonymous):

a = 6i - 6j, b = 4i + 2j like if it where something like this

OpenStudy (anonymous):

Would you follow the same operations?

OpenStudy (asnaseer):

the above is equivalent to saying that you have these two vectors:\[a=<6,-6>\]\[b=<4,2>\]The 'i' and 'j' represent the two orthogonal components of each vector.

OpenStudy (anonymous):

Ohh, Ok! Thanks Again!

OpenStudy (asnaseer):

e.g. in you question, \( = <3, 3, -8>\) is equivalent to writing:\[v=3i+3j-8k\]

OpenStudy (anonymous):

Ok, are you required to write in that form at all or is it just a teacher thing?

OpenStudy (asnaseer):

both forms are valid - use whatever method your teacher has taught you but being aware of both will help you understand vectors better

OpenStudy (anonymous):

Thanks Again!

OpenStudy (asnaseer):

yw :)

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