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Mathematics 21 Online
OpenStudy (sparrow2):

so if i have suppose y=x as f(x) and y=x-2 as f(x-2) than in the second case( y=f(x-2) ) which is the domain x or x-2? and how you get y=f(x-2) from y=f(x)=x..

OpenStudy (loser66):

Since it is a linear function, hence the -2 from x is -2 from y also. The domain of a common linear function is \(\mathbb R\), How to get y = f(x-2) from f(x)=x?? just draw y =x, then take down 2 units. |dw:1432500305489:dw|

OpenStudy (loser66):

|dw:1432500325894:dw|

OpenStudy (sparrow2):

i know that we can consider it as change in function but i;m interested in change in argument .. so we have y=f(x) and want to get y=f(x-2) why it will be rigth to 2 unit? @Loser66

OpenStudy (loser66):

same

OpenStudy (loser66):

since it is a linear function, move to the right same as move down if it is not, like \( y = x^2\), then \(y = x^2 -2 \) is different from \(y = (x-2)^2\)

OpenStudy (sparrow2):

i understand but have you prove that it will go right to 2 unit( by argument change not function change) @Loser66

OpenStudy (loser66):

You meant prove y = x-2 is y =x moves 2 units to the right? ok make T table for both.|dw:1432502437387:dw|

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