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Mathematics 22 Online
OpenStudy (heyitslizzy13):

can anyone explain this?

OpenStudy (heyitslizzy13):

OpenStudy (xapproachesinfinity):

hi there!

OpenStudy (heyitslizzy13):

hi :)

OpenStudy (xapproachesinfinity):

so you want understand what exactly in this question

OpenStudy (heyitslizzy13):

the process of doing it, I wasn't taught this but it's extra credit so I'd like to know how to find the answer

OpenStudy (xapproachesinfinity):

sure :) you do understand what the symbol tell us yes?

OpenStudy (heyitslizzy13):

I don't :/

OpenStudy (xapproachesinfinity):

\[\sum _{i=1}^{100}\] do you understand what this means

OpenStudy (heyitslizzy13):

I searched it and it says it stand for the element of?

OpenStudy (heyitslizzy13):

stands*

OpenStudy (xapproachesinfinity):

ok so that symbol is telling to sum from 1 to 100 but what are we summing here that is what we want to find yes

OpenStudy (heyitslizzy13):

yes

OpenStudy (xapproachesinfinity):

it stands for summation from a starting point to an ending point so no big deal really

OpenStudy (heyitslizzy13):

okay

OpenStudy (xapproachesinfinity):

ok so what we are summing here is the natural number starting from 1 to 100 since we have \[\sum_{i=1}^{100}i\]

OpenStudy (heyitslizzy13):

what do the i's stand for?

OpenStudy (xapproachesinfinity):

that i'm going to explain now :)

OpenStudy (xapproachesinfinity):

that i is telling us for the index i=1 put the first term 1 for i=2 put 1+2 for i=3 put 1+2+3 and so tell 100

OpenStudy (xapproachesinfinity):

the index is the bottom i+ the i that is on the line is telling us what are we summing up \[\sum_{i=1}^{100}i=1+2+3+4+5+6+....+100\]

OpenStudy (xapproachesinfinity):

you see how it goes say you have this \[\sum_{k=0}^{8}4k\] what you gonna do is \[\sum _{k=0}^{8}4k=4(0)+4(1)+4(2)+4(3)+4(4)+4(5)+4(6)+4(7)+4(8)\]

OpenStudy (heyitslizzy13):

ohh okay I see, is there like a way to do it or do i just have to add?

OpenStudy (xapproachesinfinity):

good question!

OpenStudy (xapproachesinfinity):

actually there a famous formula proved by gauss (a mathematician) that helps you add up a large summation of natural numbers feel free to check how this guy finds the formula

OpenStudy (xapproachesinfinity):

i will give you the formula and if you are interested see some video that show it came along

OpenStudy (xapproachesinfinity):

so the formula is : \[1+2+3+4+...+n=\frac{n(n+1)}{2}\] if we are summing n natural numbers

OpenStudy (heyitslizzy13):

for n do I plug in 100 since it is the last # to be added?

OpenStudy (xapproachesinfinity):

here in your example we are summing from 1 to 100

OpenStudy (xapproachesinfinity):

yes exactly

OpenStudy (heyitslizzy13):

wow okay thanks!!! (:

OpenStudy (xapproachesinfinity):

np dear :)

OpenStudy (xapproachesinfinity):

do check it really:) it is interesting to know how thing are developed ^_-

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