Question

Find all rational zeros:
F(x)=x^4-7x^3+3x^2+21x-18

Answer 1

really?

Answer 2

how are you supposed to find the zeros of a fourth degree polynomial?

Answer 3

What

Answer 4

I have no idea. It's the problem my teacher gave me though....

Answer 5

lol ok apparently this factors as
\[(x-1) (x-6) (x^2-3)\]

Answer 6

you know how i know it?

Answer 7

http://www.wolframalpha.com/input/?i=x%5E4-7x%5E3%2B3x%5E2%2B21x-18

Answer 8

THANK YOU

Answer 9

Lol.

Answer 10

Well if you don't know the steps the answer is useless...we can do division with (x-1) as it's a factor which then we end up with \[(x^3-6x^2-3x+18)(x-1) \] you can factor out common terms and get the result misty provided which is \[(x-6)(x^2-3)(x-1)\]

Answer 11

Thanks

Answer 12

Note (x-1) is a facto because we let x = 1, which would give us 0 for f(1), hence it is a factor, and we can do the long division.