Question

A magnetic field of magnitude B = 0.25 T is directed perpendicular to a circular loop of wire that has a radius of 0.47 m. What is the magnetic flux through the wire?

***How can I show the work for this? Thank you!!:)

Answer 1

here I am

Answer 2

hi!!

Answer 3

the situation described by your exercise, is:

Answer 4

by definition, the requested flux, is given by the susbsequent formula:
\[\Large \Phi = BS = \pi {R^2}B\]
where S is the area enclosed by our loop, namely it is the area of a circumference:
\[\Large S = \pi {R^2}\]

Answer 5

so, what is:
\[\Large \Phi = \pi {R^2}B = 3.14 \times {\left( {0.47} \right)^2} \times 0.25 = ...Weber\]

Answer 6

sorry, my computer just froze!!

but yes, we get 0.1734065 ?

Answer 7

that's right!
We can round off that result like this:
\[\Large \Phi = 0.173\;{\text{Weber}}\]

Answer 8

ohh yay!! so that is all for this problem? that is the magnetic flux? 0.173 weber? :O

Answer 9

yes! Our task is completed!

Answer 10

yay!! thank you so much!! :D

Answer 11

Thank you!! :D