P(h)=P*oe^-0.00012h In the function Po is the air pressure at the surface of the earth and h is the height above the surface of the earth, measured in meters. At what height will the air pressure be 50% of the air pressure on the earths surface? 4166.7m 0.59m 2148.9m 5776.2m
\[P(h)=P_o e^{-0.00012h}\] did you mean this? if so, do you see the solution?!
yes that is what i meant
so isnt it just P9h)=.50^-0,00012h
P(h)=.50^-0.00012h
@IrishBoy123 now what?
\[P(h) = P_{o} e^{−0.00012 \ h} \\ P(0)=P_{o} e^{−0.00012 \ (0)} = Po \\ P(H)=P_{o} e^{−0.00012 \ H} = \frac {1}{2}Po \] \[e^{−0.00012 \ H} = \frac {1}{2}\] Solve
so ln(.5)/-0.00012
-0.00012H = ln (1/2) 0.00012H = ln (2) H = ln (2) / 0.00012 same thing as yours but do you really agree with this? it's your project after all!!
yes i agree
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