Question

WILL FAN AND MEDAL!!!!!!! Question in comments

Answer 1

\[(4 x^{2}-2x - 1) - (-3x ^{3}+2)\]

Answer 2

@KendrickLamar2014

Answer 3

@Michele_Laino

Answer 4

here, you have to apply the distributive property of multiplication over addition, namely, we can write this:
\[\Large - \left( { - 3{x^3} + 2} \right) = \left( { - 1} \right) \cdot \left( { - 3{x^3} + 2} \right) = 3{x^3} - 2\]

Answer 5

so we get:
\[\large 4{x^2} - 2x - 1 - \left( { - 3{x^3} + 2} \right) = 4{x^2} - 2x - 1 + 3{x^3} - 2 = ...?\]
please continue

Answer 6

Umm

Answer 7

3x^3 + 4x^2 - 2x - 3?

Answer 8

that's right!

Answer 9

Awesome!

Answer 10

thanks! :)

Answer 11

Help with more?

Answer 12

ok!

Answer 13

^

Answer 14

here you have to combine similar terms, so we can rewrite, your expression as follows:
\[\Large 16{x^2} - 15{x^2} + 2x + 14x + 2 - 1 = ...?\]

Answer 15

And um, I don't mean to be rude but can you kinda hurry I have family on the way down from out of state.

Answer 16

31x^2 +16x +1?

Answer 17

hint:
16-15=1
2+14=16
2-1=1

Answer 18

Or x^2 +16x +1

Answer 19

that's right!

Answer 20

^

Answer 21

\[\Large 3{x^2} - 4{x^2} - 2x + 5x + 6 + 9 = ...?\]
3-4=...
-2+5=...
6+9=...

Answer 22

-x^2 + 7x + 15?

Answer 23

+3x since -2x+5x=3x

Answer 24

Huh?

Answer 25

we have +3x in place of 7x

Answer 26

So A?

Answer 27

yes!
\[3{x^2} - 4{x^2} - 2x + 5x + 6 + 9 = - {x^2} + 3x + 15\]

Answer 28

^

Answer 29

\[\Large 3{x^2} - 5{x^2} + 5x - 7x + 3 + 2 = ...\]
+3-5=...
5-7=...
3+2=...

Answer 30

B, -2x^2 - 2x + 5?

Answer 31

perfect!

Answer 32

^

Answer 33

-12x +15?

Answer 34

here we have to apply the distributive property of multiplication over addition, so we can write:
\[ - 3\left( {4x + 5} \right) = - 3 \cdot \left( {4x} \right) + \left( { - 3} \right) \cdot 5\]

Answer 35

-12x + 15?

Answer 36

no, since -3*5 = -15

Answer 37

So, -12x - 15?

Answer 38

correct!

Answer 39

3 more please?

Answer 40

ok!

Answer 41

^

Answer 42

first question:
as before, we have to apply the distributive property of multiplication over addition, so we can write:
\[\begin{gathered}
5{k^2}\left( { - 6{k^2} - 2k + 6} \right) = \hfill \\
\hfill \\
= 5{k^2} \cdot \left( { - 6{k^2}} \right) + 5{k^2} \cdot \left( { - 2k} \right) + 5{k^2} \cdot 6 = ... \hfill \\
\end{gathered} \]

Answer 43

C? -k^4 + 3k^3 + 11k^2

Answer 44

no, because you have to compute multiplications, not additions:
5*(-6)=-30
5*(-2)=-10
5*6=30

Answer 45

D

Answer 46

yes!

Answer 47

And the second one is -42^2?

Answer 48

second question:
\[\left( { - 6x} \right) \cdot \left( {7{x^2}} \right) = \left( { - 6} \right) \cdot 7 \cdot x \cdot {x^2} = ...\]
again you have to compute multiplications only

Answer 49

-42x^2*

Answer 50

no, because x*x^2 = x^(1+2)=...

Answer 51

-42x^3?

Answer 52

that's right!

Answer 53

third question:

Answer 54

13y^2 -11y?

Answer 55

or y^2 -3y

Answer 56

as before, for previous exercises, we have to apply the distributive property of multiplication over addition, or also the foil method is a good procedure which we can apply. In both cases we can write this:

Answer 57

Is it A or C?

Answer 58

\[\begin{gathered}
\left( {6{y^2} - 4y} \right)\left( {7{y^2} - 7y} \right) = \hfill \\
= \left( {6{y^2}} \right) \cdot \left( {7{y^2}} \right) + \left( {6{y^2}} \right) \cdot \left( { - 7y} \right) + \left( { - 4y} \right) \cdot \left( {7{y^2}} \right) + \left( { - 4y} \right) \cdot \left( { - 7y} \right) = ... \hfill \\
\end{gathered} \]

Answer 59

D?

Answer 60

Sorry I am being such a trouble

Answer 61

next step is:
\[\begin{gathered}
\left( {6{y^2} - 4y} \right)\left( {7{y^2} - 7y} \right) = \hfill \\
= \left( {6{y^2}} \right) \cdot \left( {7{y^2}} \right) + \left( {6{y^2}} \right) \cdot \left( { - 7y} \right) + \left( { - 4y} \right) \cdot \left( {7{y^2}} \right) + \left( { - 4y} \right) \cdot \left( { - 7y} \right) = \hfill \\
= 42{y^4} - 42{y^3} - 28{y^3} + 28{y^2} \hfill \\
\end{gathered} \]

Answer 62

sorry I have made a big error

Answer 63

here is the right step, we have to compute the sum not multiplication

Answer 64

\[\begin{gathered}
\left( {6{y^2} - 4y} \right) + \left( {7{y^2} - 7y} \right) = \hfill \\
= 6{y^2} + 7{y^2} - 4y - 7y \hfill \\
\end{gathered} \]

Answer 65

6+7=13
-4-7=-11

Answer 66

Sorry again for my error!

Answer 67

do you recognize, the right option?

Answer 68

A?

Answer 69

My first choice

Answer 70

@Michele_Laino hello?

Answer 71

that's right!