Given: x - 6 1/3≤ 1 1/2 Choose the solution set. a. {x | x ∈ R, x ≤ 7 5/6} b. {x | x ∈ R, x ≤ 7 2/5} c. {x | x ∈ R, x ≤ 5 1/6}
Can you be a bit clearer in how the inequality is actually written? Do you mean: \[(x - 6)(\frac{ 1 }{ 3}) \le (1)(\frac{ 1 }{ 2 })\]
yes, sorry i dont know how to type it that way
That's no problem, thanks for clarifying. So, essentially we're looking to rearrange the inequality to find x on its own, from which we can identify the solution set. For starters, we can multiply out the brackets on each side of the inequality sign: \[\frac{ 1 }{ 3}x -\frac{ 1 }{ 3 }(6) \le \frac{ 1 }{ 2 }\] \[\frac{ 1 }{ 3 }x - 2 \le 2\] I'll leave it to you to finish this one off. Remember that we can treat the inequality sign as an '=' sign effectively when we're adding, subtracting or multiplying positive values across both sides in order to get x on its own (i.e. we ignore it). If we multiply across by a negative number, then we must 'flip' the sign of the inequality when doing so (i.e. it would change from <= to >= here), but we don't have to worry about this at all for this question. The first thing to do is to get rid of the '-2' on the left-hand side. Once you have done that , you can get rid of the fraction which x is multiplied to on this side by multiplying across the whole inequality appropriately. This should leave you with x on its own, hopefully. Good luck!
Sorry once more, I've made another mistake, this time in the inequality I have worked out above in my answer. Once you multiply out the brackets, the right-hand side should clearly by 1/2 and not 2 as I show above. So, the overall equation should be: \[\frac{ 1 }{ 3 }x - 2 \le \frac{ 1 }{ 2 }\] Apologies for the error! :)
thank you for walking me through that, and that is no problem (:
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