Question

If 50 g of liquid water [C = 4,180 J/(kg*K)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred?

A. 10.5 J

B. 10.5 kJ

C. 72.7 J

D. 100 kJ

**Not sure about this one! thank you:)

Answer 1

here we have to apply this formula:
\[\Large Q = cm\Delta T = 4180 \times 0.05 \times \left( {348 - 298} \right) = ...Joules\]

Answer 2

okay!! so we get 10450 Joules? so about 10.5 kJ ?

Answer 3

correct!

Answer 4

yay!! :D thanks!!! :D

Answer 5

thanks!!!!! :D