Question

solve ln 5+ln (2x)=5 round your answer to the nearest hundredth. Please help.

Answer 1

write in single ln form product rule \[\large \rm ln x + \ln y = \ln ( x \times y )\]

Answer 2

Could you go on? because I'm still confused.

Answer 3

let's say x represent 5
and 2x represent y
how would you condense ln in single ln form ?
just like in this equation \[\large \rm ln x + \ln y = \ln ( x \times y )\]

Answer 4

I keep getting 1/2

Answer 5

\[\large \rm ln x + \ln y = \ln ( x \times y )\]
\[\large\rm ln 5 + \ln (2x) = ?\]

Answer 6

show your work how did you get 1/2 ?

Answer 7

Well it goes like ln(2x)=−5+5
ln(2x)=0
(e)0=2x
e0=2x
1=2x

2x=1
x=1/2

Answer 8

alright first step is wrong
why did you subtract 5 ?

Answer 9

it's ln 5 at left side
not just 5

Answer 10

My choices are
1.1484
2.11.17
3.71.71
4.0.02
also since Since 5 does not contain the variable to solve for, we move it to the right-hand side of the equation by subtracting 5 from both sides. If I'm wrong can you direct me in the direction of the right answer by showing me how to do it?

Answer 11

alright nope you can't subtract 5
bec it's ln(5)

Answer 12

Okay, well can you show me, please ?

Answer 13

first of all apply product property
\[\large \rm ln x + \ln y = \ln ( x \times y )\]
\[\large\rm ln 5 + \ln (2x) = ln(5 \times2x) \]
there is a plus sign so you have to apply product property

Answer 14

\[\huge\rm ln (5 \times 2x) =5\]
now take e both side
do it let me know what yo uget

Answer 15

3.85244

Answer 16

Wait I did something wrong

Answer 17

yes try again :-)

Answer 18

Sorry, I'm not sure what to do. I'm pretty brain dead because I have been working on my math final since like 7 am.

Answer 19

math final ?

Answer 20

is it from a test ?? :-)

Answer 21

Mhm, I have about 16 questions left out of 50.

Answer 22

sorry...

Answer 23

We help study for tests we DO NOT help you ON the test. Please go find a diffrent website to cheat from because we will not help you with a test refer the the Terms and conditions which YOU agreed to before you decided to come to this site. thanks.

Answer 24

http://goo.gl/NJQwpm

Answer 25

http://www.nig.gr/brJ

Answer 26

I didn't feel like it was cheating, I was just asking for explanation rather than the answer, you know?

Answer 27

Well I'll close the question, I wasn't aware, sorry.

Answer 28

Would you teacher want to see what U know or what we know?