Question

log(3x+5)-log(x-5)=log(8)

Answer 1

i got it so log(3x+5/x-5)=log8 and dont know where to go from there

Answer 2

hint: \[\huge\rm log_b x = \log_b y\]
\[\huge\rm\cancel { log_b} x = \cancel{\log_b} y\]
x=y

Answer 3

so 3x-5/x-5=8

Answer 4

yep now simple algebra

Answer 5

i got -20 but the answer is 9

Answer 6

how did you get -20?

Answer 7

i cross multiplied

Answer 8

so 8x-40=3x+5

Answer 9

solve for x

Answer 10

i got -20

Answer 11

show ur work

Answer 12

oh i found my mistake thank you!

Answer 13

r u sure ? u got it ?

Answer 14

yep! can i ask you one more though?

Answer 15

alright

Answer 16

log8+3logx=3 which i know is log8+logx^3=3 but what do you do if theres no log on the other side?

Answer 17

apply log properties
which one you should apply ?

Answer 18

change of base?

Answer 19

yeah or convert log to exponential form just like we did before

Answer 20

nope there is a variable so you can't use change of base formula

Answer 21

how would you do that though because isnt it 8x^3=3

Answer 22

log (8x^3) = 3

Answer 23

\[\log = \log_{10}\]

Answer 24

but idk how you would make that exponential