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((cosx*cotx)/(1-sinx)) -1 = cscx verify identity
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\[\frac{ cosxcotx }{ 1-sinx } -1 = cscx\]
verify identity
Cosx*cotx=cosx*cosx/sinx=cos^2x/sinx
how?
@shamim
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cot(x) = cos(x)/sin(x), right? so cos(x)*cot(x) = cos(x)*cos(x)/sin(x) = cos^2x/sinx
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