Mathematics
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OpenStudy (anonymous):
A fair coin is tossed 4 times in a row. If X is the number of heads counted, which table gives the probability distribution of X?
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OpenStudy (anonymous):
@rational
OpenStudy (anonymous):
OpenStudy (rational):
whats the probability for getting heads on all 4 coins ?
OpenStudy (anonymous):
1/2?
OpenStudy (rational):
how ?
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OpenStudy (rational):
may i know why do you think it is 1/2
OpenStudy (anonymous):
its a 50/50 chance to land on head.
OpenStudy (rational):
its a 50/50 chance to land head on one coin
OpenStudy (rational):
but when you have four coins, the probability for landing heads on "ALL" four coins need not be 1/2 right
OpenStudy (rational):
the probability is actually 1/2*1/2*1/2*1/2 = 1/16
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OpenStudy (anonymous):
so what like 1/4?
OpenStudy (anonymous):
oh sorry. 4 coins. my bad
OpenStudy (rational):
Yes, another question
whats the probability for getting NOT getting heads in any of the four coins ?
OpenStudy (anonymous):
1/2 each so total would be another 1/16?
OpenStudy (rational):
Yep!
so P(X=0) is 1/16
and P(X=4) is also 1/16
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OpenStudy (rational):
Now, whats the probability of getting exactly ONE head ?
OpenStudy (rational):
P(X=1) = ?
OpenStudy (anonymous):
I would think 1/2 but i know thats not it
OpenStudy (rational):
one way to get exactly ONE head is :
H T T T
OpenStudy (rational):
notice that there are 3 other ways to get exactly ONE head :
T H T T
T T H T
T T T H
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OpenStudy (rational):
so the probability for getting exactly ONE head is 4/16 = 1/4
OpenStudy (rational):
see if that makes sense
OpenStudy (anonymous):
Yes it does, I see what you mean now. okay.
OpenStudy (rational):
look at the options
OpenStudy (anonymous):
A?
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OpenStudy (rational):
|dw:1432817476450:dw|
OpenStudy (rational):
Yes! our work so far matches perfectly with option A
OpenStudy (anonymous):
Yes thats why I said A, the work matches A and not others