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How much heat does it take to melt 2.5 kg of lead when it is at its melting point (m.p. = 327.5ºC; ∆Hf = 2.04 * 10^4 J/kg) ? A. 6.2 × 10^1 J B. 8.2 × 10^3 J C. 5.1 × 10^4 J D. 1.7 × 10^7 J **thank you!:)
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is \Delta H the enthalpy change?
i am not sure :/ i think so... it looks like this |dw:1432830397213:dw|
i did not type the subscript clearly!
I think that it is the fusion enthalpy change
ohh okay! :)
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so, I think that the requested amount Q of heat is given by the subsequent computation: \[\Large Q = \Delta {H_f} \times m = ...Joules\]
okay, so i plug in like this? 2.04 * 10^4 * 2.5 ?
yes!
yay! so we get 51000? so the answer is choice C? 5.1 * 10^4 J ?
that's right!
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yay! Thank you:D
Thank you!!!!! :)
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