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Mathematics 17 Online
OpenStudy (anonymous):

help please i will reward you

OpenStudy (anonymous):

Harry can rake the leaves in the yard 8 hours faster than his little brother Jimmy can. If they work together, they can complete the job in 3 hours. Using complete sentences, explain each step in figuring out how to determine the time it would take Jimmy to complete this job on his own.

OpenStudy (kash_thesmartguy):

what's the question?

OpenStudy (anonymous):

Harry can rake the leaves in the yard 8 hours faster than his little brother Jimmy can. If they work together, they can complete the job in 3 hours. Using complete sentences, explain each step in figuring out how to determine the time it would take Jimmy to complete this job on his own.

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

x = time it takes Jimmy to do the job alone x-8 = time it takes Harry to do the job alone (since he can do it 8 hrs faster) you can form this equation based off of the given word problem \[\Large \frac{1}{x} + \frac{1}{x-8} = \frac{1}{3}\] solve for x to get your answer

OpenStudy (anonymous):

okay so now i just have to find the common denominator and combine?

OpenStudy (anonymous):

would it take him 26 hours to do it on hs own @jim_thompson5910

OpenStudy (anonymous):

@mns

jimthompson5910 (jim_thompson5910):

\[\Large \frac{1}{x} + \frac{1}{x-8} = \frac{1}{3}\] \[\Large 3x(x-8)*\left(\frac{1}{x} + \frac{1}{x-8}\right) = 3x(x-8)*\left(\frac{1}{3}\right)\] \[\Large 3x(x-8)*\left(\frac{1}{x}\right) + 3x(x-8)*\left(\frac{1}{x-8}\right) = 3x(x-8)*\left(\frac{1}{3}\right)\] \[\Large 3(x-8) + 3x = x(x-8)\] I'll let you take over

jimthompson5910 (jim_thompson5910):

In step 2, I multiply both sides of the equation by the LCD 3x(x-8) to clear out all the fractions (which are fully cleared out by step 4)

jimthompson5910 (jim_thompson5910):

oh sorry line 3 is cut off, it is supposed to be \[3x(x-8)*\left(\frac{1}{x}\right) + 3x(x-8)*\left(\frac{1}{x-8}\right) = 3x(x-8)*\left(\frac{1}{3}\right)\]

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