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Mathematics 8 Online
OpenStudy (anonymous):

The claim is that the proportion of peas with yellow pods is equal to 0.25 (or 25%). The sample statistics from one experiment include 570 peas with 111 of them having yellow pods. Find the value of the test statistic.

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

Hey there

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

don`t understand the question!!!

OpenStudy (anonymous):

Nope

OpenStudy (amistre64):

what do you not understand about the question?

OpenStudy (anonymous):

How to put the equation into my TI83 to obtain the value

OpenStudy (anonymous):

Of the test statistic

OpenStudy (amistre64):

looks like we have 1 sample, and are tring to evaluate a proportion ...

OpenStudy (amistre64):

what does 2nd, vars, tests (maybe calc) get for us?

OpenStudy (amistre64):

http://cfcc.edu/faculty/cmoore/TI-STAT.htm

OpenStudy (anonymous):

ok I have it up but how would I input the information?

OpenStudy (amistre64):

OpenStudy (amistre64):

tell me what the inputs are ... are what youd assume they should be

OpenStudy (amistre64):

po = ? n = ? x = ?

OpenStudy (anonymous):

po=0.25 n=600 x= no sure about

OpenStudy (anonymous):

not 600 I meant 570

OpenStudy (amistre64):

po is good, now from the information we have only 2 numbers left to work 570 peas with 111 of them having yellow pods

OpenStudy (anonymous):

Yes. So, then to put that into an equation is what I am having difficulty with.

OpenStudy (amistre64):

there is no equation, you simply type them into the calculator po = .25 n=570 x=111 the last thing to do is to determine the type of tails we want to test.

OpenStudy (amistre64):

you can work it as an equation, but then why would we have used the function to start with?

OpenStudy (anonymous):

Oh ok... So how would I input it into the ti83?

OpenStudy (amistre64):

i already covered that ... with links and pictures and everything.

OpenStudy (anonymous):

Ok, I will try it out.

OpenStudy (amistre64):

once you get to the function and fill in those 3 parts, theres one last part to cover. let me know when you are there.

OpenStudy (anonymous):

ok, I have it calculated

OpenStudy (amistre64):

and what is your value?

OpenStudy (amistre64):

also, what did you choose for the last portion? \(\ne\)p, <p, or >p

OpenStudy (anonymous):

All I see is: z=-3.047 p=.0011 p^=.1947 n=570

OpenStudy (amistre64):

your test stat is z :)

OpenStudy (anonymous):

I just clicked on calculate

OpenStudy (amistre64):

thats fine, we werent asked anything that would alter the z value.

OpenStudy (anonymous):

OMG thank you thank you!!!

OpenStudy (amistre64):

another way to have done is: z = (111/570 - .25)/sqrt(.25(1-.25)/570) which is -3.047 http://www.wolframalpha.com/input/?i=%28111%2F570+-+.25%29%2Fsqrt%28.25%281-.25%29%2F570%29

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