In the triangle below, the ratio that represents csc θ is 4/5 True False
\[\huge\rm csc \theta =\frac{ 1 }{ \sin \theta }\] and sin theta \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
how do i find the opposite and the hypotenuse? @Nnesha
@jim_thompson5910
|dw:1433387988660:dw|
the hypotenuse is ALWAYS the longest side it is always opposite the 90 degree angle |dw:1433388057774:dw|
with relation to angle theta (symbol \(\large \theta\)), the 12 is the opposite side because it is the furthest from angle theta that you can get the 9 is the adjacent side because it is touching the angle theta |dw:1433388118783:dw|
71.62
oh wait its 4/5 so its true
well as Nnesha pointed out, sine = opposite/hypotenuse so you just found out that sin(theta) = 4/5
but you need csc(theta)
i got 71.62
idk how you got that
idk whats the formula from there
sin(theta) = 4/5 1/sin(theta) = 5/4 ... take the reciprocal of both sides csc(theta) = 5/4
so 5/4 is the answer
yes and not 4/5 like it states up at the very top
ohh ok thank youu!
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