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Mathematics 11 Online
OpenStudy (anonymous):

matrix 2

OpenStudy (anonymous):

OpenStudy (anonymous):

ihatethisevenmoremore

OpenStudy (anonymous):

it is not C

OpenStudy (anonymous):

this takes a bit but not too bad ready?

OpenStudy (anonymous):

this is where you say "yeah i am ready even though i hate this even more"

OpenStudy (anonymous):

yeah i am ready even though i hate this even more

OpenStudy (anonymous):

ok the last line has 1, -2 which means \(z=-2\)

OpenStudy (anonymous):

the second to last line has 1, 1, 3 which means \[y+z=3\] we know \(z=-2\) so \[y-2=3\]or \[y=5\]

OpenStudy (anonymous):

the first line has 1, a, 2, 2 which means \[x+ay+2z=2\] we know \(y=5\) and \(z=-2\) so we have \[x+4a+2\times (-2)=2\] or \[x+5a-4=2\]

OpenStudy (anonymous):

solve for \(a\) and get your answer you can do it or you want help?

OpenStudy (anonymous):

oops i meant "solve for \(x\)"

OpenStudy (anonymous):

its B? then

OpenStudy (anonymous):

yeah B

OpenStudy (anonymous):

okay 1 or 2 more then i promise ill let you go :'(

OpenStudy (anonymous):

i have to say for someone starting out with matrices this is a dumb question but whatever

OpenStudy (anonymous):

yeah i always stay up until 3 to help...

OpenStudy (anonymous):

OpenStudy (anonymous):

I think its D?

OpenStudy (anonymous):

@freckles this one is on you, i always screw this up

OpenStudy (anonymous):

C is out

OpenStudy (anonymous):

i mean matrix C is out

OpenStudy (anonymous):

oh maybe not let me shut up

OpenStudy (freckles):

if we do a m by n times a n by k the we are cool because this will result in a m by k matrix you just have to make sure the inner numbers match if you know what I mean

OpenStudy (freckles):

|dw:1433573306445:dw|

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