What is the solution to equation, square root of (2x+8) -6=4
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OpenStudy (anonymous):
Helppppp
OpenStudy (anonymous):
Does it look like this? \[\large \sqrt{2x+8}-6=4\]
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
Well the first step is to get the 6 to the other side. Can you do that?
OpenStudy (anonymous):
yes you add it to the 4 to get 10. but I have no idea what to do after that
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OpenStudy (anonymous):
So now it will look like this \[\large \sqrt{2x+8}=10\] So we're going to get x out of the square root by squaring both sides. So \[\large \sqrt{2x+8}^{2}=10^{2}\]
OpenStudy (anonymous):
so is it going to be, (2x+8)(2x+8)=20?
OpenStudy (anonymous):
No. \[\large \sqrt{x}^{2} = x\] So \[\large \sqrt{2x+8}^{2} = 2x+8\] And \[\large 10^{2}=10 \times 10\]
OpenStudy (anonymous):
So 2x+8=100. and then you get ride of the 8 by subtracting on the other side and the divide by 2. would the answe be x=46?
OpenStudy (anonymous):
Yes, that would be it. Good job :)
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