Question

question inside!:)

Answer 1

oh no! it got uneven! :/ that is just one line for choice D!

Answer 2

here we have to apply this formula:
\[\Large E = \frac{{hc}}{\lambda } = \frac{{6.63 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{730 \times {{10}^{ - 9}}}} = ...Joules\]

Answer 3

2.72465754E-19? choice A is the solution?

Answer 4

that's right!

Answer 5

yay! thanks!:)

Answer 6

:)