Question

Check my answer for a medal?

Answer 1

hello

Answer 2

hi

Answer 3

Factor completely 8m^3 - 12m^2 + 4m.
I got 4 (2m^3 - 3m^2 + m)

Answer 4

well, first step, you should try factoring it out.

Answer 5

lets see:

\(\large\color{slate}{\displaystyle \sqrt{(-3)^2-4\cdot2\cdot1}=\sqrt{9-8}=\sqrt{1}=1}\)

Answer 6

Oh no, this is gonna be difficult to choose who I give this medal too

Answer 7

you're on the right track but you're not quite done yet

notice how each of the terms in the parantheses still has m, right? you can factor out m

Answer 8

yeah, your are not done. You can factor it more.
(What I did just now, is the discriminant test)

Answer 9

factor out 4m instead of 4.

Answer 10

factor out of 4m, and even then not done

Answer 11

now you have 4m(2m^2-3m+1)

Answer 12

Alright. I got 4m (2m^2 - 3m) is this correct?

Answer 13

and as I demostrated with discriminant test, it is factorable

Answer 14

GOOD SO FAR.
NOW, LAST STEP

Answer 15

2m^2-3m+1 => 2m^2-2m-m+1

Answer 16

Alright, alright alright. Listen guys, I'm really getting overwhelmed with all of you trying to help. I appreciate you guys trying to help but I can't focus on so many people. So, I will focus on Solomon since he was the first to respond on this post. Sorry

Answer 17

ok. it's cool.

Answer 18

Sorry

Answer 19

So we are at this point:
4m(2m^2-3m+1)

Answer 20

now, look at 2m^2-3m+1 alone.

you can factor it, and I will give you a hint: re-write it as
2m^2-2m-m+1

Answer 21

u got dis XD

Answer 22

Alright. so I got (-2m+1) (-m+1)

Answer 23

yes, that ic correct.

Answer 24

YAY!!!

Answer 25

Pro tip. It is easier to look at when the coefficients are positive.

Answer 26

You can take two negatives out..... it is a little bit strange to me the way you wrote it.

What I meant to see was rather.
\(\large 2m^2-3m+1\)

\(\large 2m^2-2m-m+1\)

\(\large 2m(m-1)-m+1\)

\(\large 2m(m-1)-1(m-1)\)

\(\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)\)

\(\large (2m-1)(m-1)\)

Answer 27

hint: -1 x -1 = 1

Answer 28

same.

Answer 29

nice job tho

Answer 30

You can take two negatives out..... it is a little bit strange to me the way you wrote it.

What I meant to see was rather.
\(\large 2m^2-3m+1\)

\(\large 2m^2-2m-m+1\)

\(\large 2m(m-1)-m+1\)

\(\large 2m(m-1)-1(m-1)\)

\(\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)\)

\(\large (2m-1)(m-1)\)

Answer 31

I mean the way you did it is perfectly fine. As long as it is correct. But I am just letting you know my point of view from the side.

Answer 32

it's just easier to manage without negative coefficients... nobody likes negative XD

Answer 33

Alright, but the answer (2m-1) (m-1) isn't an option. Well, there is. But, there is a 4m in front of it. 4m(2m - 1) (m - 1)

Answer 34

Would I just go with that?

Answer 35

what are the options?

Answer 36

yes, because you are factoring
4m(2m^2-3m+1)

Answer 37

you are not factoring just the 2m^2-3m+1
I took a look at it alone, so that we can factor it, but the 4m does't go away.

Answer 38

Alright. Thanks guys! And Plasma, the options are

2m (4m2 - 6m + 2)
4 (2m3 - 3m2 + m)
4m (2m - 1)(m - 1)
4m (2m2 - 3m)

Answer 39

go with that, we never dropped the 4m.

Answer 40

ok, you pick one:)

Answer 41

yup.

Answer 42

all urs

Answer 43

Thanks guys! I appreciate the fact that you walked me through it Solomon! Sadly not a lot of people would be willing to walk me through these problems. But the ones that do are awesome!

Answer 44

I do this for the pleasure of helping people. plus, solomon told me to walk people through on problems XD

Answer 45

I told you that? Have I? Well in my mind I was like "I hope he isn't giving out answers like many users here do" .... :) lol

Answer 46

Anyway, you welcome.

Answer 47

Yeah, I appreciate that those users just straight up give me the answer. I also want to learn how to do the problem so I won't ask for help as often.

Answer 48

So I would prefer them to walk me through them

Answer 49

ok:)

Answer 50

have a good evening

Answer 51

You too.