Any idea?

Question

Any idea?

anonymous · Answer

attachment

anonymous · Answer

@mathmate 

Hello. This one is tough one for me! PLease help

anonymous · Answer

@wrik003

anonymous · Answer

2 solutions... x = 3 and x = 2... do u need a detailed explanation as before?

anonymous · Answer

Oh yes please! If anyone who have different idea please let me know

anonymous · Answer

hold on a minute

mathmate · Answer

Find common denominator, subtract, and cross multiply to give the quadratic equation  x^2-5x+6=0, or (x-3)(x-3)=0.
However, check the two solutions x=2 or x=3 by substituting into the original equation.  $One$ of them gives a zero for denominator, hence is not a solution.

welshfella · Answer

yes - the one that is not a solution is called extraneous.

anonymous · Answer

So I'm correct?

anonymous · Answer

@mathmate 
@welshfella

anonymous · Answer

only 3 is a solution... I was wrong; a bit!

anonymous · Answer

So, can you tell me which one is correct? @welshfella @mathmate

anonymous · Answer

I'm lost!!!

anonymous · Answer

workout:

anonymous · Answer

now plugging 2 into the original equation leads to infinity - infinity; which is absurd. but 3 gives a correct solution. check for it in the same way as for 2

welshfella · Answer

there's an error in your last line
multiplying through by (x-2)(x+2)   gives (x-2)(x+2) on right hand side

mathmate · Answer

@KittyT 
You have to do some work too!  lol
Read through my response and do some checking, and you will find your answer AND also understand why.  OR read the last posts of @wrik003 to find the answer! 
Good luck!

welshfella · Answer

it should be

5(x + 2) - 20 = x^2 - 4

anonymous · Answer

I got 2 solutions....

welshfella · Answer

what are they/

anonymous · Answer

x=3 and x=2

anonymous · Answer

u are stating something as exact as mine @welshfella. the only difference being that u have cross-multiplied x^2 -4 with 1! Hope u get it!

anonymous · Answer

@KittyT check my 2nd last post & u shall find the answer

anonymous · Answer

is it your workout?

anonymous · Answer

I think there's one solution which is x=3

anonymous · Answer

yes... whose else's workout could it be? my local time right now is 23:42! how do u suppose I'll get external; help?!

anonymous · Answer

So it's right?

anonymous · Answer

yes... my workout is correct... as verified my @mathmate.

anonymous · Answer

So my final answer is 1 solution only!

anonymous · Answer

yes... correct