Question

if the quadratic equation ax^2+bx+6=0 does not have two distinct real roots, then the least value of 2a+b is

Answer 1

@ganeshie8

Answer 2

@nincompoop @Luigi0210

Answer 3

@dan815

Answer 4

@UnkleRhaukus

Answer 5

what is the discriminant of that quadratic?

\[\Delta = b^2-4ac\]

Answer 6

b^2-24a<0

Answer 7

when ∆ > 0 the are two real roots

there is only one root when ∆ = 0

is ∆ < 0 there are no real roots

Answer 8

yes b^2-4ac<0

Answer 9

then

Answer 10

i think you want
\[b^2-24a\leq0\]

Answer 11

yes so how to find 2a+b least value

Answer 12

solve for a (as a function of b)

Answer 13

how can we find

Answer 14

solve the inequality

Answer 15

can u solve for this

Answer 16

\[-2\sqrt{6}a<b<2\sqrt{6}a\]

Answer 17

how???????????

Answer 18

\[b^2-24a\leq0\\
b^2\leq24a\\
\frac{b^2}{24}\leq a\]

Answer 19

then

Answer 20

2a + b =

Answer 21

\[2a+b\geq2\cdot\frac{b^2}{12}+b\]

Answer 22

following?, not following? @kanwal32