Question

1234
Points: 2Question 2
Ten employees of a nursing home, having been given a course in cardiopulmonary resuscitation (CPR), scored 17, 20, 12, 14, 18, 23, 17, 19, 18, and 15 on a test administered after the completion of the course. Find the standard deviation and variance.
Standard deviation = 2.97; Variance = 8.81
Standard deviation = 8.81; Variance = 8.81
Standard deviation = 8.81; Variance = 2.97
Standard deviation = 3.13; Variance = 9.59

Answer 1

@ZoMbAsH

Answer 2

@welshfella
@TheSmartOne

Answer 3

hmm see if i remember this
First find the mean of all the values by adding up all the values then dividing by 10

Answer 4

k

Answer 5

17.3

Answer 6

the subtract the mean from each of the values
so for 17 this will give 17-17.3 = -0.7
do this for all 10 values

Answer 7

I'll be honest I have no idea :(

Answer 8

why u choose 17?

Answer 9

just as an example

Answer 10

oh i see

Answer 11

then you square each of the results and add them up. Finally divide the total by n