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Mathematics 15 Online
OpenStudy (anonymous):

Having trouble with statistics, specifically probability.

OpenStudy (anonymous):

is there a specific problem or concept you need explained?

OpenStudy (anonymous):

A local video store owner is examining his two stores, the one on 29th Avenue and the other on Division. The 29th store does 70% of the dealer's business and the Division store does the rest. In the Division store, 40% of all rentals are DVDs. In the 29th store, 30% of all rentals are DVDs. If a customer is selected at random, what is the probability that she will rent a DVD?

OpenStudy (anonymous):

sorry, it's a question on paper, so I had to type it out.

OpenStudy (amistre64):

what are some ideas you have considered?

OpenStudy (amistre64):

storeA does 70% of the dealer's business storeB does the rest. In B, 40% of all rentals are DVDs. In A, 30% of all rentals are DVDs. If a customer is selected at random, what is the probability that she will rent a DVD? P(storeA and DVD), or P(storeB and DVD)

OpenStudy (anonymous):

okay

OpenStudy (amistre64):

lets imagine we have 1000 people. we seperate them into 2 different rooms: 70% in roomA, and 30% in roomB ------------------------------- we ask the 700 people in roomA if they got a DVD, and 30% of them say yes we ask the 300 people in roomB if they got a DVD, and 40% of them say yes -------------------------------- so, out of 1000 people, how many are there altogether that have a DVD? 7*30, and 3*40 .. 210+120 = 330 --------------------------------- 330 people out of 1000 have a DVD. so our probability is?

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