Question

rearrange to isolate A

Answer 1

\[H = K + Log (\frac{ A }{ C })\]

Answer 2

i thought A = e^(H-K) x C was correct but it's not...

Answer 3

h - k = log(a/c)
log(a/c) = log a - log c
so log a - log c = h - k
proceed

Answer 4

\[\log(\frac{ A }{ C }) = \log A - \log C \]
\[\log A - \log C = h - k\]
\[\log A = h - k + \log C\]

Answer 5

ok and then do i use "e" to cancel log?

Answer 6

@rishavraj

Answer 7

ooo yeahh.... :))