Given: AB = CE CD = EF Prove: AB = DF Statement: AB = DF Reason: Substitution Property of Equality Statement: DE = DE Reason: Subtraction Property of Equality Statement: CE = DF Reason: Transitive Property of Equality Statement: CD = DE Reason: Substitution Property of Equality Statement: CE = EF Reason: Transitive Property of Equality
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here is my resoning: \[\Large \begin{gathered} DF = DE + EF = \hfill \\ = DE + CD = \hfill \\ = CE = \hfill \\ = AB \hfill \\ \end{gathered} \]
thx :D can you help me some more? how can you give medals just asking..
ok!
how tho?
you have to click on the "Best Response" button
thanks! :)
anytime :D can you help with a couple more?
ok!
:D
Points A(-2, 4), B(1, 3), C(4, -1) and D form a parallelogram. What are the coordinates of D? (5, 5) (0, 0) (1, -2) (1, 0) (3, 4)
hint: we have the subsequent drawing: |dw:1436446847339:dw|
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