Given: AB = CE
CD = EF
Prove: AB = DF
Statement: AB = DF
Reason: Substitution Property of Equality
Statement: DE = DE
Reason: Subtraction Property of Equality
Statement: CE = DF
Reason: Transitive Property of Equality
Statement: CD = DE
Reason: Substitution Property of Equality
Statement: CE = EF
Reason: Transitive Property of Equality
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
if anyone helps ill become their fan
OpenStudy (michele_laino):
here is my resoning:
\[\Large \begin{gathered}
DF = DE + EF = \hfill \\
= DE + CD = \hfill \\
= CE = \hfill \\
= AB \hfill \\
\end{gathered} \]
OpenStudy (anonymous):
thx :D can you help me some more?
how can you give medals just asking..
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OpenStudy (michele_laino):
ok!
OpenStudy (anonymous):
how tho?
OpenStudy (michele_laino):
you have to click on the "Best Response" button
OpenStudy (michele_laino):
thanks! :)
OpenStudy (anonymous):
anytime :D can you help with a couple more?
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OpenStudy (michele_laino):
ok!
OpenStudy (anonymous):
:D
OpenStudy (anonymous):
Points A(-2, 4), B(1, 3), C(4, -1) and D form a parallelogram. What are the coordinates of D?
(5, 5)
(0, 0)
(1, -2)
(1, 0)
(3, 4)
OpenStudy (michele_laino):
hint:
we have the subsequent drawing:
|dw:1436446847339:dw|