Question

math

Answer 1

what have you tried??

(a) If first 3 MUST be answered, then how many are remaining, and how many out of them are to be answered?

Answer 2

oh so its 7c5

Answer 3

thats right :)

Answer 4

(b) Atleast 4 out of 1st 5,

so 2 cases :
4 out of first 4 and another 4 out of another 5
OR
5 out of 1st 5 and another 3 out of remaining 5

Answer 5

**
4 out of first 5 and another 4 out of another 5
OR
5 out of 1st 5 and another 3 out of remaining 5

Answer 6

2c1?

Answer 7

4 out of first 5 = 4C5
4 out of another 5 = 4C5

"4 out of first 5 and another 4 out of another 5" = 4C5 + 4C5

do it similarly for
"5 out of 1st 5 and another 3 out of remaining 5"

Answer 8

sorry
***
"4 out of first 5 and another 4 out of another 5" = 4C5 * 4C5

Answer 9

woah!
5C4, not 4C5 :P

Answer 10

Omg. 2c1 so far from 5c4. Darn.

Answer 11

Thank you so much @hartnn

Answer 12

so you got it?
and welcome ^_^

Answer 13

yes yes =)