OpenStudy (anonymous):

Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their axis of symmetry.

2 years ago
OpenStudy (anonymous):

Treat them as if you were completing the square

2 years ago
OpenStudy (anonymous):

so\[x^2+6x-1=(x+3)^2-10\], the bracket sets them up looking like an a^2-10 (a=x+3), like any normal quadratic they start at a line of symmetry of x=0, so the translation of -10 means is irrelevant and the transformation +3 means the line of symmetry shifted to the left by 3 (i.e line of symmetry is x=-3)

2 years ago
OpenStudy (anonymous):

Try it for the rest then you can compare their lines of symmetry

2 years ago
OpenStudy (anonymous):

I see!

2 years ago
OpenStudy (anonymous):

so for the 2nd one, take out the the negative. -x^2+2=-(x^2-2), line of symmetry is x=2

2 years ago
OpenStudy (anonymous):

Yep! I understand now. Thank you so much!

2 years ago
OpenStudy (anonymous):

Whoops, I've run into some trouble again. When comparing the line of symmetry for h(x), which I found to be positive 1, I realized it can't be the right answer. What am I doing wrong?

2 years ago
OpenStudy (anonymous):

@14mdaz

2 years ago
OpenStudy (anonymous):

so factorising 2 out \[2x^2-4x+3=2(x^2-2x)+3=2(x-1)^2-1+3\] line of symmetry should be positive 1

2 years ago
OpenStudy (anonymous):

oh after the 2 should still be 2(((x-1)^2)-1) but that still wouldnt make a difference to the line of symmetry

2 years ago
OpenStudy (anonymous):

Exactly! However, according the practice module, that can't be right. Is there a possibility that f(x) is equivalent to positive 3 rather than negative as we had originally thought?

2 years ago
OpenStudy (anonymous):

its still gonna be +3 in the brackets so thats a -3 translation, did you type up f(x) wrong?

2 years ago
OpenStudy (anonymous):

Well, in the practice module, it gave these options for the ordering of the functions by line of symmetry (least to greatest):

2 years ago
OpenStudy (anonymous):

A. f, g, h

2 years ago
OpenStudy (anonymous):

B. h, g, f C. g, h, f D. h, f, g

2 years ago
OpenStudy (anonymous):

so it should be in the order (small to greatest), f(x), h(x), g(x) :/

2 years ago
OpenStudy (anonymous):

But our findings would suggest f, h, g, like you said, but it's not an option.

2 years ago
OpenStudy (anonymous):

It must be an error in the module.

2 years ago
OpenStudy (anonymous):

oh sorry i made a mistake with g

2 years ago
OpenStudy (anonymous):

you dont need to bracket it because its -x^2, its an upside down quadratic so its symmetry is still 0 not 2

2 years ago
OpenStudy (anonymous):

thus the order would be f, g, h?

2 years ago
OpenStudy (anonymous):

yes

2 years ago
OpenStudy (anonymous):

Thank you for clearing that up! I was driving myself crazy. It's funny that I didn't notice the error in g(x) either.

2 years ago
OpenStudy (anonymous):

it was my fault i thought -(x^2-2) was -(x-2)^2 XD

2 years ago