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Mathematics 15 Online
OpenStudy (anonymous):

question in comments please help

OpenStudy (anonymous):

arrange these expressions from smallest to largest 32 3/5, 64 2/3, 81 1/4, 49 1/2, 124 2/3

rishavraj (rishavraj):

u can write 32 as 2^2 64 as 2^6 81 as 3^4 and go on

rishavraj (rishavraj):

\[32^{\frac{ 3 }{ 5 }} = (2^5)^{\frac{ 3 }{ 5 }} = 2^{5 \times \frac{ 2 }{ 5 }} = 2^2 = 4 \]

rishavraj (rishavraj):

write 64 as 4^3

OpenStudy (anonymous):

thank you

rishavraj (rishavraj):

were those fractions as exponentx???just assuring

OpenStudy (anonymous):

no they weren't exponents they were normal fractions

rishavraj (rishavraj):

hold on

rishavraj (rishavraj):

it was like \[32\frac{ 3 }{ 5 } ~~~~ or ~~~~~32^{\frac{ 3 }{ 5 }}\]

OpenStudy (anonymous):

The question is asking from them to be ordered from largest to smallest

rishavraj (rishavraj):

hmmmm ???

OpenStudy (anonymous):

the numbers I gave you, I need them ordered from largest to smallest

rishavraj (rishavraj):

yeahhh bt is it in form of \[32\frac{ 3 }{ 5 }\]

rishavraj (rishavraj):

or \[32^{\frac{ 3 }{ 5 }}\]

OpenStudy (anonymous):

the first one

rishavraj (rishavraj):

u mean \[32\frac{ 3 }{ 5 }~~~~ u ~~~can~~write ~~~\it ~~~ \frac{ 163 }{ 5 } = 32.6\]

OpenStudy (anonymous):

I got the answer thanks for your help

OpenStudy (anonymous):

hey those fractions are exponents

OpenStudy (anonymous):

@rishavraj

rishavraj (rishavraj):

as i told write 32 as 2^5 and so on......

rishavraj (rishavraj):

give a try

OpenStudy (anonymous):

I don't get it

rishavraj (rishavraj):

see remember \[(a^m)^n = a^{mn}\] its \[32^{\frac{ 3 }{ 5 }} \] write 32 as 2^5 so it would be \[(2^5)^{\frac{ 3 }{ 5 }} = 2^{5 \times \frac{ 3 }{ 5 }} = 2^3 = 8\]

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