Question

chem

Answer 1

@Photon336

Answer 2

@Photon336

Answer 3

Ask yourself what happens at your equivalent point?

You've added equimolar quantities of acid/base hence neutralization

Answer 4

what do you think? do you know where is the equivalence point in the graph?

Answer 5

I'm pretty sure it's C. Is that right?

Answer 6

I think you are right, I would choose the same answer

Answer 7

Thanks! :)

Answer 8

That's still within the equivalence point it, says "above equivalence point" so I think it would be 12

Answer 9

You can eliminate 2 and 8 right away because one is the equivalent point where the other is past it.

If you see at the equivalencen point you add equimolar quantities of acid and base so the term A-/HA drops out and you are left with pH= pKA and at that flat line where 8 is you'll have the greatest resistance to change in pH.

Answer 10

Sorry pH of 2 is not past but before the equivalence point.

Answer 11

I agree with @Cuanchi