Question

hi ppl i need ur help

Answer 1

my question is-
if u want too build a pile of 100coins(1and 2dinars) such that, number of coins between any two '2' dinar coins is not equal to five, then what are the maximum number of 2 dinar coins that can be included in the pile?

Answer 2

we have a pile of 100 coins which has both 1dinar and 2 dinar coins. the questions asks us to tell the maximum number of 2 dinar coins in the pile if the number of coins between any '2' 2dinar coins is nt five.

Answer 3

wait r u taking the value of total coins to be 100 dinars??

Answer 4

:) v don't want the value to be 100 we want total number of coins to be 100 :)

Answer 5

So total 100 coins, with both kinds.
Since question does not specify that there \(has\) to be 1 dinar coins between the two-dinars, then
Minimum number of 1 dinar coins = 1
what is the maximum number of two-dinars?

Answer 6

we have 1 more condition @mathmate that is - there are no '2' 2dinar coins with a gap of 5 coins between then

Answer 7

.

Answer 8

i m getting the answer 50

Answer 9

in this case there will be no '2' 2dinar coins with a gap of 5coins between them
so in this case we can see that the number of 1dinar nd 2dinar coins is equal so there are 50 2dinar coins

Answer 10

but i am not sure that 50 is the MAXIMUM value of 2dinar coins...this answer is obtained frm the case which i made i donno there can be another case in which the answer can exceed 50.

Answer 11

My bad, I didn't read the question properly.
As a start, we can try with 6x2, then 6x1, then 6...
222222111111222222111111....2222221111112222
for a total of 52 2-dinars.
We'll investigate to see if there is a better arrangement.

Answer 12

the answer by my method is nt 50 its less than that

Answer 13

@imqwerty
I find 8 patterns of 222222111111 giving 48 2's out of 96 coins.
The remaining 4 coins can be 2's, giving a total of 48+4=52 coins of 2 dinars.
Would you like to show your calculations?