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Mathematics 15 Online
OpenStudy (anonymous):

Solve for x: |x + 2| + 16 = 14 A. x = −32 and x = −4 B. x = −4 and x = 0 C. x = 0 and x = 28 D. No solution

OpenStudy (anonymous):

@HectorH

OpenStudy (anonymous):

i think its D

OpenStudy (janu16):

No solution

OpenStudy (anonymous):

ok i was right thnx :)

OpenStudy (anonymous):

We subtract 16 from both sides to get \[\left| x+2 \right| = -2\] Then thats impossible since absolute value bars keep it from going negative.

OpenStudy (anonymous):

yup :) thnx

OpenStudy (janu16):

@jkl5149 its no solution

OpenStudy (anonymous):

@Janu16 Yes.

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