Question

WILL MEDAL AND FAN!!!
Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

and is there any way to put the answer in this format?

https://suwannee.owschools.com/media/g_geo_2013/8/q255_x.gif

Answer 1

@uybuyvf

Answer 2

@AaronAndyson

Answer 3

@jamesr

Answer 4

yeah

Answer 5

dO YOU KNOW WHAT TO DO?

Answer 6

i think so hold up

Answer 7

We know that the triangle formed by the two radii and the chord is
an equilateral triangle, all angles are 60 degrees, which is 1/6 of
360 degrees
:
Find area inside the 60 degree arc
1/6*pi*8= 35.51


:
Find the area of the equilateral triangle
1/2*8*SQRT8^2-4^2 = 27.71 sq/in
:
Find the area of the shape enclosed by the 60 degree arc and the chord
35.51 - 27.71 = 7.8 sq/in
:
Find the area of the larger segment
pi*8^2 - 7.8 = 193.26 sq/inches