The position vector of a particle is given by \( r = r_0(1-at)t\) , where t is the time and a as well as \(r_0\) are constant. After what time the particle returns to the starting time
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OpenStudy (nincompoop):
latex is not displaying properly on my end
OpenStudy (nincompoop):
is that r naught (r sub zero)
OpenStudy (abhisar):
Yes, it's r naught
OpenStudy (abhisar):
I got it.
OpenStudy (nincompoop):
so t, a and r_0 are all constant? the english is badly phrased
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OpenStudy (nincompoop):
\(test \)
OpenStudy (nincompoop):
okay now it is working
OpenStudy (abhisar):
No only \(\sf r_0 ~and~ a\) are constants.
\(\sf r = r_0t-r_0at^2\\ \Rightarrow (taking ~r=0) r_0t = r_0at^2 \\ \Rightarrow t =1/a\)
OpenStudy (nincompoop):
After what time the particle returns to the starting time
OpenStudy (abhisar):
Yes, it shoud be t = 1/a
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OpenStudy (abhisar):
*should
OpenStudy (nincompoop):
i keep getting disconnected
OpenStudy (abhisar):
It's ok, I solved it. Thanks for helping me though c:
OpenStudy (nincompoop):
by simplification, you are left with \(at=1 \)
OpenStudy (nincompoop):
your displacement must be set to zero (position function)