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Mathematics 20 Online
OpenStudy (abhisar):

The position vector of a particle is given by \( r = r_0(1-at)t\) , where t is the time and a as well as \(r_0\) are constant. After what time the particle returns to the starting time

OpenStudy (nincompoop):

latex is not displaying properly on my end

OpenStudy (nincompoop):

is that r naught (r sub zero)

OpenStudy (abhisar):

Yes, it's r naught

OpenStudy (abhisar):

I got it.

OpenStudy (nincompoop):

so t, a and r_0 are all constant? the english is badly phrased

OpenStudy (nincompoop):

\(test \)

OpenStudy (nincompoop):

okay now it is working

OpenStudy (abhisar):

No only \(\sf r_0 ~and~ a\) are constants. \(\sf r = r_0t-r_0at^2\\ \Rightarrow (taking ~r=0) r_0t = r_0at^2 \\ \Rightarrow t =1/a\)

OpenStudy (nincompoop):

After what time the particle returns to the starting time

OpenStudy (abhisar):

Yes, it shoud be t = 1/a

OpenStudy (abhisar):

*should

OpenStudy (nincompoop):

i keep getting disconnected

OpenStudy (abhisar):

It's ok, I solved it. Thanks for helping me though c:

OpenStudy (nincompoop):

by simplification, you are left with \(at=1 \)

OpenStudy (nincompoop):

your displacement must be set to zero (position function)

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