help i will fan and medal answer already solved need to figure out out how she got the numbers
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OpenStudy (anonymous):
I sort of said it wrong it's not slope I always just got to slope be you would use pathegorean theorem for the two sides so 3^2+4^2=c^2 so the length would be root 13 so the perimeter would be root 13 + root 13 +6+6
12+2sqrt13
OpenStudy (anonymous):
someone already helped me on this but idk where she got the numbers from
OpenStudy (anonymous):
this is the equation she solved
find the perimeter of the shape
OpenStudy (anonymous):
@Skielerlucas04 can you help or do you know anyone who can
OpenStudy (anonymous):
@blackeistien238821 help please
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OpenStudy (anonymous):
idk wut grade work dis
OpenStudy (anonymous):
geometry 10th grade
OpenStudy (anonymous):
i only 7th grade sorry
OpenStudy (anonymous):
wish i could help
OpenStudy (anonymous):
oh it thanks but do you know any that can help me
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OpenStudy (anonymous):
jim_thompson5910
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
i think she got the numbers from the points but used slope intercep form to find the length of the sides
OpenStudy (anonymous):
so how did she get the numbers from slope intercept
jimthompson5910 (jim_thompson5910):
Focus on the right triangle I have drawn in red. This triangle has legs of 2 and 3.
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jimthompson5910 (jim_thompson5910):
a = 2
b = 3
c = unknown
a^2 + b^2 = c^2
2^2 + 3^2 = c^2
solve for c to get c = ???
OpenStudy (anonymous):
15
OpenStudy (anonymous):
sorry 12
jimthompson5910 (jim_thompson5910):
nope on both
OpenStudy (anonymous):
13
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jimthompson5910 (jim_thompson5910):
2^2 + 3^2 = c^2
4 + 9 = c^2
c^2 = 13
c = ??
OpenStudy (anonymous):
what do i do with 13
OpenStudy (anonymous):
13 times 13 is 169
jimthompson5910 (jim_thompson5910):
the opposite actually, you take the square root of 13
jimthompson5910 (jim_thompson5910):
\[\Large c = \sqrt{13}\]
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OpenStudy (anonymous):
that 3.605551275
OpenStudy (anonymous):
4
jimthompson5910 (jim_thompson5910):
The length of AB is \(\Large \sqrt{13}\) units long. The same reasoning applies to CD.
OpenStudy (anonymous):
or 4 lol
OpenStudy (anonymous):
i got 4 for CD
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
CD is the same length as AB
OpenStudy (anonymous):
but how did she get 19
jimthompson5910 (jim_thompson5910):
both are exactly sqrt(13) units long
they are approximately 3.60555127546399 units long
jimthompson5910 (jim_thompson5910):
I don't see any 19
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OpenStudy (anonymous):
like what IIIIIIIIIIIIIIIIII said
OpenStudy (anonymous):
12+2sqrt13 equals 19
jimthompson5910 (jim_thompson5910):
I'd have to see the full problem + instructions
OpenStudy (anonymous):
19 was the final answer
jimthompson5910 (jim_thompson5910):
Oh nvm, you're looking for the perimeter
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jimthompson5910 (jim_thompson5910):
two sides are 6
6+6 = 12
jimthompson5910 (jim_thompson5910):
the other two sides are \[\Large \sqrt{13}\]
jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{13}+\sqrt{13} = 2\sqrt{13}\]
OpenStudy (anonymous):
how are they 6
jimthompson5910 (jim_thompson5910):
Perimeter = \(\Large 12+2\sqrt{13} \approx 19.2111025509\) which rounds to 19
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jimthompson5910 (jim_thompson5910):
BC = AD = 6
jimthompson5910 (jim_thompson5910):
you just count the spaces for the horizontal or vertical segments
OpenStudy (anonymous):
oh ok
jimthompson5910 (jim_thompson5910):
|dw:1437692895844:dw|
OpenStudy (anonymous):
were is 13 from
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jimthompson5910 (jim_thompson5910):
|dw:1437692932875:dw|
jimthompson5910 (jim_thompson5910):
it's not just 13. It's the square root of it
OpenStudy (anonymous):
why cant it be sqrt 12 or another number why is it 13
jimthompson5910 (jim_thompson5910):
because that's what you get when you solve for c in 2^2 + 3^2 = c^2
jimthompson5910 (jim_thompson5910):
it's \(\sqrt{13}\) and NOT 13
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