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OpenStudy (anonymous):
If g(x) = sqrt(x-3) and k(x) = x^2 + 5 then determine: (g*k)(7)
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OpenStudy (anonymous):
just multiply the two functions and evaluate at x=7
OpenStudy (anonymous):
How do you multiply them?
OpenStudy (anonymous):
(x-3) * (x^4 + 25). Is this what you are suppose to get when you multiply them?\[x ^{5}-3x ^{4}+25x-75\]
jimthompson5910 (jim_thompson5910):
you forgot the square root over the x-3
jimthompson5910 (jim_thompson5910):
(g*k)(7) is the same as g(7) * k(7)
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OpenStudy (anonymous):
I squared the both equations so I can get rid of the square root.
jimthompson5910 (jim_thompson5910):
find g(7) and k(7). Then multiply those results
jimthompson5910 (jim_thompson5910):
squaring x^2 + 5 does not give x^4 + 25
also, squaring can only be done when you square both sides of an equation
OpenStudy (anonymous):
Would the answer be 216 then?
OpenStudy (anonymous):
Oh I keep forgetting some steps. But I got the answer doing what you said.
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jimthompson5910 (jim_thompson5910):
it's not 216
OpenStudy (anonymous):
x^2 + 5 = 7^2 + 5 = 49 + 5 = 54
sqrt(x - 3) = sqrt(7 - 3) = sqrt(4) = 2
54 * 2 = 108
I forgot to sqrt the 4 earlier.
jimthompson5910 (jim_thompson5910):
108 is correct
OpenStudy (anonymous):
Thanks!
jimthompson5910 (jim_thompson5910):
no problem
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