If 400 feet of fencing is used to enclose a rectangular plot of land that borders a river, what is the maximum area that can be enclosed?
It's pretty east to start out. Use the formulas: A = w * h P = 2h + w where P is the perimeter of the fence (400 ft), h is the length of one of the 2 parallel sides, and w is the length of the side that is parallel to the river.
okay so 400 = 2h + w now what?
system of equations?
so solve for either h or w in that equation and substitute that into the Area formula
okay so w = 200/h
no quite
so 400 = 2h + 200/h
w = 400 - 2h
argh okay ...
so 400 = 2h + (400 - 2h)
so that w should be substituted into the Area formula: A = w * h so A = (400 - 2h) * h
A = 400 -2h^2
A = 400h - 2h^2
and now just find the derivative and set if equal to 0?
and yes. take the derivative, set to 0, and that will give you h. you can find w from that, which will give you the total area
so then h = 100 right?
indeed it does!
is w just the x coordinate at x =100?
i mean y coordinate?
sure. if you're mapping w (y-coord) against h (x-coord).
okay so then my area would be 15000?
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