Question

Find the exact value of tan inverse

Answer 1

tan theta = opp / adj

Answer 2

(there is no inverse)

Answer 3

this is a dumb question.. but what does the theta sign look like?

Answer 4

theta : \(\theta\)

Answer 5

that's the sign I used but I thought it meant inverse :0

Answer 6

\[\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}\]\[\Downarrow\]\[\theta = \tan^{-1}\left(\frac{\text{opposite}}{\text{adjacent}}\right)=\arctan\left(\frac{\text{opposite}}{\text{adjacent}}\right)\]

Answer 7

the question is only asking you to find \(\tan\theta\),

you don't have to compute the value of theta,

Answer 8

It's saying the equation has too many equal signs

Answer 9

what is the length of the side opposite to theta in the diagram?

Answer 10

is 6 the opp and 2 and 5 the adj?

Answer 11

yes,
opp = 6
and
adj = 2√5

Answer 12

my calculator said it was 1/2 as the answer, but it said that 1/2 is not correct

Answer 13

\(\tan\theta = \dfrac{6}{2\sqrt 5}\)

Answer 14

now cancel the common factor

Answer 15

what's the common factor?

Answer 16

\[\tan\theta = \dfrac{6}{2\sqrt 5}=\dfrac{2\times3}{2\times\sqrt 5}=\]

Answer 17

\[\tan \emptyset \frac{ 6}{ 5 }=\frac{ 3 }{ 5 }\]

Answer 18

now rationalize the denominator
\[\tan\theta = \frac{6}{2\sqrt 5}=\frac{3}{\sqrt 5}=\frac{3}{\sqrt 5}\times\frac{\sqrt5}{\sqrt5}=\]

Answer 19

20..?

Answer 20

\[\frac{3}{\sqrt 5}\times\frac{\sqrt5}{\sqrt5}=\frac{3\times\sqrt5}{\sqrt5\times\sqrt5}\]
now simplify the denominator

Answer 21

would it be 1 because 5 can go into 5 once?

Answer 22

\[\sqrt5\sqrt5=\sqrt5^2= .....\]

Answer 23

i'm not even sure how to go about that :o

Answer 24

\[√x^2 = x\]

Answer 25

oh gosh

Answer 26

ikr

Answer 27

my options don't even make sense then

Answer 28

we are very close to one of those

Answer 29

what is the square root of five squared?

Answer 30

5? I think

Answer 31

oh wait i did that wrong

Answer 32

yes, so

what is our final answer?

Answer 33

5 squared over

Answer 34

3 I wanna say