Mathematics
14 Online
OpenStudy (hellokitty17):
Solve U = 0.5CV2 for C.
C = U over 2V C = U over 2V squared C = 2U over V C = 2U over V squared
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OpenStudy (anonymous):
\[U=0.5CV^2\]
looks right?
OpenStudy (hellokitty17):
@jcoury
oregonduck (oregonduck):
yes
OpenStudy (anonymous):
idk on this one
OpenStudy (anonymous):
multiply by 2 on both sides
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OpenStudy (anonymous):
can i ask you guys some questions when ur done
OpenStudy (hellokitty17):
then
oregonduck (oregonduck):
i will give 3 medals for the answer, sure
OpenStudy (anonymous):
\[U \times 2 = 2 \times 0.5CV^2\]
OpenStudy (anonymous):
what do ya get?
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OpenStudy (anonymous):
this one is easy, trust me
oregonduck (oregonduck):
\[1.0CV ^{2}\]
OpenStudy (hellokitty17):
I don't understand how to do this that is why I asked
OpenStudy (anonymous):
\[2U=CV^2\]
oregonduck (oregonduck):
ks that the answer?
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OpenStudy (anonymous):
now divide both sides by V^2
OpenStudy (anonymous):
\[\frac{ 2U }{ V^2 } = \frac{ CV^2 }{ V^2 }\]
oregonduck (oregonduck):
is that the answer?
OpenStudy (hellokitty17):
so what is the answer?!
OpenStudy (anonymous):
@jcoury just ask i have no problem helping ppl 2 or 3 at once
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OpenStudy (anonymous):
nah, you need to simplify it
OpenStudy (anonymous):
k hold on
OpenStudy (anonymous):
\[\frac{ 2U }{ V^2 }=C\]
OpenStudy (anonymous):
thats your answeer
OpenStudy (anonymous):
@saseal check your messages
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
OpenStudy (anonymous):
guys its Saseal's birthday today!
oregonduck (oregonduck):
Happy Birthday @saseal
OpenStudy (anonymous):
ty
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oregonduck (oregonduck):
:)
OpenStudy (anonymous):
lol
OpenStudy (hellokitty17):
HAPPY B-DAY!!! How old are you?!
OpenStudy (anonymous):
24
OpenStudy (hellokitty17):
Sweet!!! Any plans for today?!
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OpenStudy (anonymous):
watch it
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
i just felt that was appropriate
OpenStudy (anonymous):
i have a few more questions can i ask them?
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OpenStudy (anonymous):
maybe 1 or 2 fast ones, i have some engineering problems to do also :(
OpenStudy (anonymous):
okay hold on
OpenStudy (anonymous):
OpenStudy (anonymous):
and if you have time
OpenStudy (anonymous):
i think i did the 2nd question wrong earlier
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OpenStudy (anonymous):
so c for 2 right