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Chemistry 22 Online
OpenStudy (anonymous):

A liquid is placed in an evacuated, sealed flask. When will this closed system reach dynamic equilibrium? When all of the liquid has evaporated to form a vapor When liquid and vapor are present but evaporation stops When the rate of evaporation equals the rate of condensation When the volume of liquid equals the volume of vapor

OpenStudy (anonymous):

@taramgrant0543664 b?

OpenStudy (taramgrant0543664):

B makes sense because the rate of condensation is much slower than the rate of evapouration

OpenStudy (anonymous):

@taramgrant0543664 that was wrong

OpenStudy (taramgrant0543664):

Wait I didn't really like that answer so I wanted to double check and it should have been c. I assumed that evapouration would get ahead but it stays constant the condensation speeds up to accomidate making the rates equal

OpenStudy (anonymous):

Two gases are placed in a sealed flask and allowed to react. Which statement is true about the concentrations of the reactants and products when this closed system reaches dynamic equilibrium? They will be equal and constant. They will be equal but continuously changing. They will not necessarily be equal, and they will be continuously changing. They will not necessarily be equal, but they will be constant.

OpenStudy (anonymous):

this one was wrong too we had picked c

OpenStudy (taramgrant0543664):

It could've been d

OpenStudy (anonymous):

it was thanks

OpenStudy (anonymous):

What is the oxidation number of fluorine (F) in F2? +1 −1 0 −3

OpenStudy (anonymous):

d?

OpenStudy (anonymous):

@taramgrant0543664

OpenStudy (taramgrant0543664):

They should be electrically neutral

OpenStudy (taramgrant0543664):

When F2 bond to another, the oxidation # on each atom is 0. If oxidation state is maintained at -1, it would lead the molecule to have a net -2 charge. Such oxidation # assignment is inaccurate, since F2 molecules are electrically neutral.

OpenStudy (anonymous):

so 0 would be correct

OpenStudy (taramgrant0543664):

Yes

OpenStudy (anonymous):

Which of the following describes an element that is oxidized in a reaction? It gains electrons during a reaction. It has a decrease in its oxidation number. Al yields Al3+ + 3e− F2 + 2e− yields 2 F−

OpenStudy (anonymous):

a?

OpenStudy (anonymous):

@sweetburger

OpenStudy (taramgrant0543664):

In oxidation you. Lose electrons

OpenStudy (anonymous):

so b? @taramgrant0543664

OpenStudy (taramgrant0543664):

C is an oxidation reaction, it's not B because if you lose electrons you become more positive increasing the oxidation number, it's not D as that is a reduction reaction and a is describing the reduction reaction

OpenStudy (anonymous):

Which of the following chemical reactions is an oxidation-reduction reaction? CuSO4 + BaCl2 yields BaSO4 + CuCl2 AgNO3 + NaCl yields AgCl + NaNO3 Pb(NO3)2 + 2NaCl yields PbCl2 + 2NaNO3 Zn + H2SO4 yields ZnSO4 + H2

OpenStudy (anonymous):

b? @taramgrant0543664

OpenStudy (taramgrant0543664):

Check the charges on each element for the product side and reactant side. If any element had a change in its charge, it's an oxidation/reduction reaction. AgNO3 + NaCl --> AgCl + NaNO3 Reactant side: Ag has a charge of +1 N has a charge of + 5 O has a charge of - 2 (-2 * 3 = -6 total) Na has a charge of +1 Cl has a charge of -1 Product side: Ag has a charge of +1 Cl has a charge of -1 Na has a charge of +1 N has a charge of +5 O has a charge of -2 No species in the reaction had a change in charge meaning it's not a reduction/oxidation reaction.

OpenStudy (anonymous):

so d is corrrect?

OpenStudy (taramgrant0543664):

Yes D is correct

OpenStudy (anonymous):

Consider the following reaction: Cl2 + 2NaBr yields 2NaCl + Br2 Which element is oxidized and which is reduced in the reaction? Br is reduced and Na is oxidized. Cl is reduced and Br is oxidized. Cl is reduced and Na is oxidized. Na is reduced and Br is oxidized.

OpenStudy (anonymous):

a? @taramgrant0543664

OpenStudy (taramgrant0543664):

Left side Cl -> 0 Na -> +1 Br -> -1 Right side Cl -> -1 Na-> +1 Br-> 0 Lose electrons oxidized, gain electrons reduced

OpenStudy (anonymous):

so c

OpenStudy (taramgrant0543664):

Cl is being reduced, but Ana the charge remains the same so it is not being oxidized or reduced

OpenStudy (anonymous):

B IS CORRECT?

OpenStudy (taramgrant0543664):

Yes it is B, Br is losing electrons and therefore oxidized

OpenStudy (anonymous):

What is true of an element that was reduced in a chemical reaction? It lost electrons. It gained electrons. It increased electronegativity. It decreased electronegativity.

OpenStudy (anonymous):

A? @taramgrant0543664

OpenStudy (taramgrant0543664):

If it loses electrons it's oxidized, if it gains electrons it's reduced

OpenStudy (anonymous):

d?

OpenStudy (taramgrant0543664):

If it was reduced then it should have gained electrons, it does not affect electronegativity

OpenStudy (anonymous):

b is correct?

OpenStudy (taramgrant0543664):

Yes

OpenStudy (anonymous):

Which of the following describes an element that is reduced in a reaction? It acts in the reactant that is the reducing agent. It has a decrease in its oxidation number. Cd yields Cd2+ + 2e− Zn + Cu2+ yields Zn2+ + Cu

OpenStudy (taramgrant0543664):

Well we can take out A since the reducing agent donates or loses electrons so if it loses electrons it becomes oxidized. We can also rule out B because the number wouldn't decrease it would increase

OpenStudy (taramgrant0543664):

D is a redox reaction so c is the only one specifically referring to an element that is being reduced

OpenStudy (anonymous):

@taramgrant0543664 c is wrong

OpenStudy (anonymous):

so d should be correct?

OpenStudy (taramgrant0543664):

I'm pretty sure a and b are wrong so then I guess it must be D

OpenStudy (anonymous):

ok

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