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Chemistry 17 Online
OpenStudy (anonymous):

When the oxidation number of an element decreases over the course of a reaction, that element has been ionized oxidized redoxed reduced

OpenStudy (anonymous):

@sweetburger

OpenStudy (anonymous):

@Woodward

OpenStudy (anonymous):

@ytrewqmiswi

OpenStudy (anonymous):

@blackeistien238821

OpenStudy (anonymous):

@Tsukinokami

OpenStudy (anonymous):

@abb0t @JFraser

OpenStudy (anonymous):

is it b @blackeistien238821

OpenStudy (anonymous):

do you kno @Bozhena

OpenStudy (anonymous):

d

OpenStudy (anonymous):

Which of the following describes an element that is reduced in a reaction? It acts in the reactant that is the reducing agent. It has a decrease in its oxidation number. Cd yields Cd2+ + 2e− Zn + Cu2+ yields Zn2+ + Cu

OpenStudy (anonymous):

@Bozhena what about this

OpenStudy (anonymous):

@blackeistien238821 do you kno

OpenStudy (anonymous):

Red is when an elment GAINS e'. So if you have Cd yields Cd2+ + 2e− It means that Cd ox.n 0 passed to Cd++ ox.n +2. When you see + it means atom had something less, in this case he had 2è less than Cd 0. So Cd++ GAINS two electrons and become Cd 0.

OpenStudy (anonymous):

Try to do the next reaction

OpenStudy (anonymous):

so the answer would be a?

OpenStudy (anonymous):

@Bozhena

OpenStudy (anonymous):

you tell me. If an element get reduced whan it gains electrons, and i told you that Cd++ gains two e' to get Cd.

OpenStudy (anonymous):

so which is correct b?

OpenStudy (anonymous):

@Bozhena

OpenStudy (anonymous):

both Cd and Zn get reduced.

OpenStudy (anonymous):

so the answer would be?

OpenStudy (anonymous):

@Bozhena

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