When the oxidation number of an element decreases over the course of a reaction, that element has been
ionized
oxidized
redoxed
reduced
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OpenStudy (anonymous):
@sweetburger
OpenStudy (anonymous):
@Woodward
OpenStudy (anonymous):
@ytrewqmiswi
OpenStudy (anonymous):
@blackeistien238821
OpenStudy (anonymous):
@Tsukinokami
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OpenStudy (anonymous):
@abb0t @JFraser
OpenStudy (anonymous):
is it b @blackeistien238821
OpenStudy (anonymous):
do you kno @Bozhena
OpenStudy (anonymous):
d
OpenStudy (anonymous):
Which of the following describes an element that is reduced in a reaction?
It acts in the reactant that is the reducing agent.
It has a decrease in its oxidation number.
Cd yields Cd2+ + 2e−
Zn + Cu2+ yields Zn2+ + Cu
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OpenStudy (anonymous):
@Bozhena what about this
OpenStudy (anonymous):
@blackeistien238821 do you kno
OpenStudy (anonymous):
Red is when an elment GAINS e'.
So if you have Cd yields Cd2+ + 2e−
It means that Cd ox.n 0 passed to Cd++ ox.n +2. When you see + it means atom had something less, in this case he had 2è less than Cd 0. So Cd++ GAINS two electrons and become Cd 0.
OpenStudy (anonymous):
Try to do the next reaction
OpenStudy (anonymous):
so the answer would be a?
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OpenStudy (anonymous):
@Bozhena
OpenStudy (anonymous):
you tell me.
If an element get reduced whan it gains electrons, and i told you that Cd++ gains two e' to get Cd.
OpenStudy (anonymous):
so which is correct b?
OpenStudy (anonymous):
@Bozhena
OpenStudy (anonymous):
both
Cd and Zn get reduced.
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