Question

MEDAL!!!!!!!!!!!!!

Problem stated below.

Answer 1

I did an experiment today relating to torques. The materials that I had were a meter stick, masking tape, and weights.

We had to use the ruler and place the two weights on each side, to try to make it balance to each other. Also, we had to note how far the tape (holding the weight) was from the center (or 50cm). Here is my first data:

Mass 1: 200g Distance from 50cm: 19cm
Mass 2: 100g Distance from 50cm: 36 cm

Then we had to multiply the mass times the distance for each and were asked to look for a pattern.
Here are my products:
Mass 1: 200g x 19 cm = 3800
Mass 2: 100g x 36 cm = 3600

I don't notice a pattern and need help in finding one.

Answer 2

@Nnesha

Answer 3

@ikram002p

Answer 4

looks pretty close

Answer 5

okay so you say your lab involved torque right

Answer 6

Yes

Answer 7

The real world will have small errors, not ideal... you did it correct

Answer 8

@DanJS So can my conclusion be like since they are both near of each other, it means that they are almost balanced to each other.

Answer 9

Are you discovering torque moments for the first time here, or do you know already

Answer 10

torque = (force perpendicular to the line of action) *(distance)

Answer 11

Well it is the second to last day of class, and my teacher didn't want to explain torques to us fully and just let us do the experiment. So we needed to find out pattern with the products.

Answer 12

The rotational moment about a point (here 50cm mark) = distance from that point, times the perpendicular force

Answer 13

here this is what i used to study torque last year
https://www.youtube.com/watch?v=sAMNoRBBjzg
i hope it helps :)

Answer 14

so if you have a force on an angle, you need to break into components first..

Answer 15

I just need to know if the statement that I wrote earlier would be fine for my conclusion or not.

Answer 16

hah, if your teacher is cramming it in this late, probably wont be much of it on the final

Answer 17

I already took the final. It's just an extra thing.

Answer 18

oh, is that the only single trial point you did? did you try different distances?

Answer 19

yes until the weights were balanced (almost)

Answer 20

I would say something like, The distance multiplied by the force seems almost the same... Need to try further experiments with different masses and distances to test if this is true

Answer 21

one test isn't enough

Answer 22

I did another trial, but with three different weights ( two on one side and one on the other).

Mass 1 : 100g Distance from 50cm: 28cm
Mass 2: 200g Distance from 50cm : 20cm
Mass 3: 300g( this weight was kept on the other side) Distance from 50cm: 20cm

Answer 23

@DanJS

Answer 24

ok, apply the same reasoning as before...

If a torque is clockwise it is negative, and if it is counter clockwise about a point, it is positive...

The sum of all the torques should add to zero if the thing is balanced and not moving

Answer 25

so 100*28 + 200*20 ideally would be 300*20

Answer 26

Okay I get it thanks.

I have some other questions, will you be able to help me on them?

Answer 27

This is an example of a velocity
a. 45 miles per hour
b. 34 meters per second
c. 23 centimeters per year northeast
d. 12 days per mile north
e. 0.1 milliseconds per kilometer
f. all of the above are examples of velocity

Answer 28

It's C right?

Answer 29

back

Answer 30

yes, a velocity is a vector quantity

Answer 31

has a magnitude and a direction for distance/time

Answer 32

second one

austin is out for a run. he starts at 98th street and 5th ave and runs 1km north to 110th street in 10 minutes. then, he turns left and runs 0.8km in 9 minutes. then, he turns left and runs down central park west. this takes him 11 min to run down the remaining 1.0km down to 98th street. what is the average velocity?

Answer 33

@DanJS

Answer 34

sorry, here

Answer 35

First need to draw all those vectors

Answer 36

The average velocity will be the resultant of those 3 vectors, the sum of them

Answer 37

The average velocity is the total displacement/ total time

Displacement is the start point to the end point, independent of the path

Answer 38

I got the velocity of 33.33m/s

Answer 39

I am wrong, right?

Answer 40

since they made a square, the magnitude or R is the same as the top piece

Answer 41

0.8km/9min = V_avg