Question

Find the vertex of the graph of the function.

f(x) = (x - 5)2 + 10

Answer 1

\[f(x)=(x-5)^{2}+10\]

Answer 2

f(x) = a(x-h)^2 + k --->vertex = (h,k) so vertex is (5,10)

Answer 3

(5,10)

Answer 4

thank youuuuu

Answer 5

what about this one? its a little different
Find the vertex of the graph of the function.

\[f(x) = 3x ^{2} - 18x + 24\]

Answer 6

@madhu.mukherjee.946

Answer 7

f(x)=3x^2-18x+24
completing the square
f(x)=3(x^2-6x+9)+24-27
f(x)=3(x-3)^2-3

Answer 8

This is a parabola of the standard form: A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Positive leading coefficient means parabola open upwards, has a minimum.
For given parabola:
vertex: (3,-3)

Answer 9

do u need help still?

Answer 10

thank you so much!! @madhu.mukherjee.946

Answer 11

your welcome darling:))

Answer 12

no i think i got it but thank you @Skielerlucas04 ill tell you if i dont get something else

Answer 13

ok