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Find the exact value by using a half-angle identity. cosine (5pi/12)
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\[\frac{5\pi}{12}\] is half of \[\frac{5\pi}{6}\]
then, 5pi/6 = -√3/2 ?
\[\cos^2(\frac{1}{2} \theta)=\frac{1}{2}(1+\cos(\theta)) \\ \text{ you have determined } \theta=\frac{5\pi}{6} \\ \text{ and I think you are actually saying } \cos(\frac{5\pi}{6})=\frac{-\sqrt{3}}{2} \\ \text{ because } \frac{5\pi}{6} \neq \frac{-\sqrt{3}}{2}\]
would the answer maybe be cos(5pi/12) = √2 - 2√3 /(fraction) 2 ?
what does that say
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