Question

Rewrite f(x) = –(x + 3)2 − 1 from vertex form to standard form

Answer 1

@triciaal @Hero

Answer 2

vertex form: y=a(x - h)^2+k
Standard form: y = ax^2 + bx + c

Answer 3

so i need to plug in the numbes?

Answer 4

Okay, so first thing you do is distribute the (x + 3)^2 expression. After you've distributed, multiply the expression with -1. Then, subtract -1.

Answer 5

im lost :/

Answer 6

Sorry, I think I'm explaining in a really crappy way right now. Let me reword it.

So, take your vertex form expression. –1*(x + 3)^2 − 1.
The first thing you want to do is simplify the term in parenthesis. Which is (x + 3)^2

Answer 7

F(x)=-x^2-6x-10
f(x)=x^2-6x+8
f(x)=x^2-6x-8
f(x)=x^2-8

Those are my choices btw

Answer 8

Okay, so first distribute. (x + 3)(x + 3).

Answer 9

X^2+6x+9

Answer 10

Plug it into the remaining parts of the equation! The equation is now –1*X^2+6x+9 − 1

Answer 11

Okay, so what now?

Answer 12

Simplify the rest of the equation.
–1*X^2+6x+9 − 1

Multiply (X^2+6x+9) by -1.

After you've received your answer, subtract 1 from it.

That is your equation in standard form!

Answer 13

So it's C?

Answer 14

So it's C?

Answer 15

Nope, try again.