Question

Answers need to be checked. DO NOT SPAM! I'M NOT JOKING!

Answer 1

1.) Factor out the GCF. \[16x^7-5x^5+5x^4\]

Answer 2

My answer: \[x^4(16x^3-5x+5)\]

Answer 3

2.) Factor out the GCF:\[60x^2-12xy+28x\]
My answer:\[4x(15x-3y+7)\]

Answer 4

3.) Factor by grouping. \[4x^2-8xy-3x+6y\]
My answer: \[(4x-3)(x-2y)\]

Answer 5

4.) Factor:\[x^2-x-42\]
My answer:\[-6,7\]
>>>> I'm thinking I have this down wrong or something.. <<<<

Answer 6

you don't need to solve for x ^^^ -6 and 7 are zero (x-intercept )

Answer 7

4.) Is your answer the zeros?

Answer 8

5.) Which of the following trinomials has a greatest common factor that can be factored out first? \[100x^2+140x+49\]
\[9x^2+24x+16\]
\[x^2+4x+4\]
\[8x^2+16x+8\]

Answer 9

My answer is the last one and @mathway no. My answer for number for as you can see above...

Answer 10

6.) Factor completely.
\[1-4x^2\]
My answer: \[(1-2x)^2\]

Answer 11

Then you're wrong. (x-6)(x+7) is not equal to the polynomial. You might want to check your signs.

Answer 12

Ok, thought so too!

Answer 13

6)hint apply difference of squares method

Answer 14

6.) Isn't that what I did??

Answer 15

difference of squares \[\huge\rm a^2-b^2 =(a\color{Red}{-}b)(a\color{reD}{+}b)\] one parentheses with negative sign and other one should be positive

Answer 16

\[\huge\rm -4x^2+1\] first take out the negative sign
\[\huge\rm -(4x^2-1)\]

Answer 17

So it'd be: \[2x^2-1\]?

Answer 18

that is one of the factor
(a-b)

Answer 19

Ohh! Wait. I know what I did wrong.. It'd be: \[(1-2x)(1+2x)\]

Answer 20

Is that right? John I see you spying ;)

Answer 21

well that's right
or you can leave it as \[-(2x-1)(2x+1)\]
remember we already factor out the negative sign :=)

Answer 22

thanks o^_^o

Answer 23

So the one is a negative then?

Answer 24

i would leave it as -(2x-1)(2x+1)
which is same as (-2x+1)(2x+1)